検索キーワード「1/2x+1/3y=2 1/3x+1/2y=13/6 by cross multiplication method」に一致する投稿を日付順に表示しています。 関連性の高い順 すべての投稿を表示
検索キーワード「1/2x+1/3y=2 1/3x+1/2y=13/6 by cross multiplication method」に一致する投稿を日付順に表示しています。 関連性の高い順 すべての投稿を表示

√完了しました! 2/x-1 3/y 1=2 3/x-1 2/y 1=13/6 by cross multiplication 186377

1 2x 1 3y 2 1 3x 1 2y 13 6 Solve The Pair Of Equations By Reducing Them To A Pair Of Linear Equation Youtube

1 2x 1 3y 2 1 3x 1 2y 13 6 Solve The Pair Of Equations By Reducing Them To A Pair Of Linear Equation Youtube

Web Answer x = 3 y = 2 Stepbystep explanation 2/ (x 1) 3/ (y 1) = 2 L1 18/ (x 1) 12/ (y 1) = 13 L2 L2 = 9L1 L2 18/ (x 1) 27/ (y 1) = 18 18/ (x 1) 12/ (yWebThe solution set is obviously symmetric with respect to the y axis Therefore we may assume x ≥ 0 In the domain { ( x, y) ∈ R 2 x ≥ 0 } the equation is equivalent with x 2 y 2 − 1 = x 2

2/x-1 3/y 1=2 3/x-1 2/y 1=13/6 by cross multiplication

5/x-1 1/y-2=2 6/x-1-3/y-2=1 by substitution method 140097

1 Answer 1 vote Standard from of an equation is ax by c = 0 1) y 3 = 1/2 (x 6) Cross multiplication 2y 6 = x 6 x 2y = 0 2) y 4 = 2/3 (x 5)Therefore, cost of one pencil = Rs 3 and cost of one pen = Rs 5 2 On comparing the ratios 2, b 1 /b 2 and c 1 /c 2, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident Answer (i) 5x – 4y 8 = 0 7x 6y – 9 = 0 Comparing these equation with a 1 x b 1 y c 1 = 0 a 2 x b 2 y c 2 = 0 Ex 36, 1 Solve the following pairs of equations by reducing them to a pair of linear equations(i) 1/2𝑥 1/3𝑦 = 2 1/3𝑥 1/2𝑦 = 13/6 1/2𝑥 1/3𝑦 = 2 1/3𝑥 1/2𝑦 = 13/6Let 1/𝑥 = u 1/𝑦 = v So, our equations become1/2 u 1/3 v = 2 (3𝑢 2𝑣)/(2 × 3) = 2

The Substitution Method

The Substitution Method

5/x-1 1/y-2=2 6/x-1-3/y-2=1 by substitution method

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